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Find the limiting reagent if 7.38 grams of C2H4 were reacted with 15.2 grams of O2.
4NH3+5O2=>4NO+6H2O
First we find the GFW of each reactant.
GFW of C2H4: 28
GFW of O2: 32
Next we divide the number of grams of each reactant by the GFW.
7.38/28= 0.263
15.2/32= 0.475
Finally, we multiply each of the results by the coefficient of the other reactant/
0.263x3= 0.789
0.475x1= 0.475
Because 0.475 is smaller than 0.789, we know that the limiting reagent is O2.
4NH3+5O2=>4NO+6H2O
First we find the GFW of each reactant.
GFW of C2H4: 28
GFW of O2: 32
Next we divide the number of grams of each reactant by the GFW.
7.38/28= 0.263
15.2/32= 0.475
Finally, we multiply each of the results by the coefficient of the other reactant/
0.263x3= 0.789
0.475x1= 0.475
Because 0.475 is smaller than 0.789, we know that the limiting reagent is O2.