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Find the limiting reagent if 50.9 grams of CH2F2 were reacted with 73.9 grams of O2.
2CH2F2+3O2=>2CO2+2H2O+2F2
First we find the GFW of each reactant.
GFW of CH2F2: 52
GFW of O2: 32
Next we divide the number of grams of each reactant by the GFW.
50.9/52= 0.97
73.9/32= 2.309
Finally, we multiply each of the results by the coefficient of the other reactant/
0.97x3= 2.91
2.903x2= 4.618
Because 2.91 is smaller than 4.618, we know that the limiting reagent is CH2F2.
2CH2F2+3O2=>2CO2+2H2O+2F2
First we find the GFW of each reactant.
GFW of CH2F2: 52
GFW of O2: 32
Next we divide the number of grams of each reactant by the GFW.
50.9/52= 0.97
73.9/32= 2.309
Finally, we multiply each of the results by the coefficient of the other reactant/
0.97x3= 2.91
2.903x2= 4.618
Because 2.91 is smaller than 4.618, we know that the limiting reagent is CH2F2.