You were wrong.
Find the limiting reagent if 89.7 grams of C2H3O2F were reacted with 16.0 grams of O2.
4C2H3O2F+3O2=>8CO+6H2O+2F2
First we find the GFW of each reactant.
GFW of C2H3O2F: 66
GFW of O2: 32
Next we divide the number of grams of each reactant by the GFW.
89.7/66= 1.35
16/32= 0.5
Finally, we multiply each of the results by the coefficient of the other reactant/
1.35 x 3= 4.05
0.5 x 4= 2.0
Because 2.0 is smaller than 4.05, we know that the limiting reagent is O2.
4C2H3O2F+3O2=>8CO+6H2O+2F2
First we find the GFW of each reactant.
GFW of C2H3O2F: 66
GFW of O2: 32
Next we divide the number of grams of each reactant by the GFW.
89.7/66= 1.35
16/32= 0.5
Finally, we multiply each of the results by the coefficient of the other reactant/
1.35 x 3= 4.05
0.5 x 4= 2.0
Because 2.0 is smaller than 4.05, we know that the limiting reagent is O2.