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Find the limiting reagent if 47.3 grams of PCl3 were reacted with 14.6 grams of H2O.
PCl3+3H2O=>H3PO3+3HCl
A:PCl3
B:H2O
First we find the GFW of each reactant.
GFW of PCl3: 136
GFW of H2O: 18
Next we divide the number of grams of each reactant by the GFW.
47.3/136= 0.347
14.6/18= 0.811
Finally, we multiply each of the results by the coefficient of the other reactant/
o.347 x 3= 1.041
0.811 x 1= 0.811
Because 0.811 is smaller than 1.041, we know that the limiting reagent is H2O.
PCl3+3H2O=>H3PO3+3HCl
A:PCl3
B:H2O
First we find the GFW of each reactant.
GFW of PCl3: 136
GFW of H2O: 18
Next we divide the number of grams of each reactant by the GFW.
47.3/136= 0.347
14.6/18= 0.811
Finally, we multiply each of the results by the coefficient of the other reactant/
o.347 x 3= 1.041
0.811 x 1= 0.811
Because 0.811 is smaller than 1.041, we know that the limiting reagent is H2O.