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Find the limiting reagent if 98.7 grams of C4H10S2 were reacted with 386 grams of O2.
2C4H10S2+19O2=>8CO2+10H2O+4SO3
First we find the GFW of each reactant.
GFW of C4H10S2: 122
GFW of O2: 32
Next we divide the number of grams of each reactant by the GFW.
98.7/122= 0.809
386/32= 12.06
Finally, we multiply each of the results by the coefficient of the other reactant/
o.809 x 19= 15.37
12.06 x 2= 24.12
Because 15.37 is smaller than 24.12, we know that the limiting reagent is C4H10S2.
2C4H10S2+19O2=>8CO2+10H2O+4SO3
First we find the GFW of each reactant.
GFW of C4H10S2: 122
GFW of O2: 32
Next we divide the number of grams of each reactant by the GFW.
98.7/122= 0.809
386/32= 12.06
Finally, we multiply each of the results by the coefficient of the other reactant/
o.809 x 19= 15.37
12.06 x 2= 24.12
Because 15.37 is smaller than 24.12, we know that the limiting reagent is C4H10S2.