How many grams of C would be produced if the reaction of 16.0 grams of N2 produces a 84.8% yield?
CaC2+N2=>Ca+CN2+C
we first find the theoretical yield.
10.68
We then multiply this number by the percentage yield/100
10.68 x (84.8/100)= 9.05 mol C
That result is our answer.
CaC2+N2=>Ca+CN2+C
we first find the theoretical yield.
10.68
We then multiply this number by the percentage yield/100
10.68 x (84.8/100)= 9.05 mol C
That result is our answer.