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How many grams of H2O would be produced if 59.3 grams of N2H4 were reacted with 66.7 grams of H2O2?
N2H4+2H2O2-->N24H2O
First we find the limiting reagent.
H2O2
Next we put the coefficient of the limiting reagent and the product into a ratio.
2:4
Next we divide this by the coefficient of the limiting reagent.
2/2=1 : 4/2=2
We then multiply the second number in the ratio by the number of moles in the limiting reagent.
2 x 1.96= 3.92
Finally, we multiply this result by the GFW of the product
3.92 x 18= 70.56 grams
That final number is your answer.
N2H4+2H2O2-->N24H2O
First we find the limiting reagent.
H2O2
Next we put the coefficient of the limiting reagent and the product into a ratio.
2:4
Next we divide this by the coefficient of the limiting reagent.
2/2=1 : 4/2=2
We then multiply the second number in the ratio by the number of moles in the limiting reagent.
2 x 1.96= 3.92
Finally, we multiply this result by the GFW of the product
3.92 x 18= 70.56 grams
That final number is your answer.