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How many grams of H2O would be produced if 27.3 grams of C7H16 were reacted with 138 grams of O2?
C7H16+11O2-->7CO2+8H2O
First we find the limiting reagent.
C7H16
Next we put the coefficient of the limiting reagent and the product into a ratio.
1:8
Next we divide this by the coefficient of the limiting reagent.
1/1=1 : 8/1=8
We then multiply the second number in the ratio by the number of moles in the limiting reagent.
8 x 0.275= 2.184
Finally, we multiply this result by the GFW of the product
2.184 x 18= 39.312 grams
That final number is your answer.
C7H16+11O2-->7CO2+8H2O
First we find the limiting reagent.
C7H16
Next we put the coefficient of the limiting reagent and the product into a ratio.
1:8
Next we divide this by the coefficient of the limiting reagent.
1/1=1 : 8/1=8
We then multiply the second number in the ratio by the number of moles in the limiting reagent.
8 x 0.275= 2.184
Finally, we multiply this result by the GFW of the product
2.184 x 18= 39.312 grams
That final number is your answer.