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How many grams of O2 would be produced if 93.7 grams of Na2O2 were reacted with 16.4 grams of H2O?
2Na2O2+2H2O-->4NaOH+O2
First we find the limiting reagent.
H2O
Next we put the coefficient of the limiting reagent and the product into a ratio.
2:1
Next we divide this by the coefficient of the limiting reagent.
2/2=1 : 1/2=0.5
We then multiply the second number in the ratio by the number of moles in the limiting reagent.
0.5 x 0.911= 0.455
Finally, we multiply this result by the GFW of the product
0.455 x 32= 14.567 grams
That final number is your answer.
2Na2O2+2H2O-->4NaOH+O2
First we find the limiting reagent.
H2O
Next we put the coefficient of the limiting reagent and the product into a ratio.
2:1
Next we divide this by the coefficient of the limiting reagent.
2/2=1 : 1/2=0.5
We then multiply the second number in the ratio by the number of moles in the limiting reagent.
0.5 x 0.911= 0.455
Finally, we multiply this result by the GFW of the product
0.455 x 32= 14.567 grams
That final number is your answer.