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How many grams of CO2 would be produced if 2.58 grams of C2H3OCl were reacted with 1.16 grams of CO2?
C2H3OCl+2O2-->2CO2+H2O+HCl
First we find the limiting reagent.
O2
Next we put the coefficient of the limiting reagent and the product into a ratio.
1:1
Next we divide this by the coefficient of the limiting reagent.
1/1=1 : 1/1=1
We then multiply the second number in the ratio by the number of moles in the limiting reagent.
1 x 0.036= 0.036
Finally, we multiply this result by the GFW of the product
0.036 x 44= 1.584 grams
That final number is your answer.
C2H3OCl+2O2-->2CO2+H2O+HCl
First we find the limiting reagent.
O2
Next we put the coefficient of the limiting reagent and the product into a ratio.
1:1
Next we divide this by the coefficient of the limiting reagent.
1/1=1 : 1/1=1
We then multiply the second number in the ratio by the number of moles in the limiting reagent.
1 x 0.036= 0.036
Finally, we multiply this result by the GFW of the product
0.036 x 44= 1.584 grams
That final number is your answer.