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How many grams of Br2 would be produced if 62.4 grams of CH2Br2 were reacted with 22.2 grams of O2?
2CH2Br2+3O2-->2CO2+2H2O+2Br2
First we find the limiting reagent.
CH2Br2
Next we put the coefficient of the limiting reagent and the product into a ratio.
2:2
Next we divide this by the coefficient of the limiting reagent.
2/2=1 : 2/2=1
We then multiply the second number in the ratio by the number of moles in the limiting reagent.
1 x 0.358= 0.358
Finally, we multiply this result by the GFW of the product
0.358 x 160= 57.28 grams
That final number is your answer.
2CH2Br2+3O2-->2CO2+2H2O+2Br2
First we find the limiting reagent.
CH2Br2
Next we put the coefficient of the limiting reagent and the product into a ratio.
2:2
Next we divide this by the coefficient of the limiting reagent.
2/2=1 : 2/2=1
We then multiply the second number in the ratio by the number of moles in the limiting reagent.
1 x 0.358= 0.358
Finally, we multiply this result by the GFW of the product
0.358 x 160= 57.28 grams
That final number is your answer.