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How many grams of CO2 would be produced if 64.2 grams of C4H10O were reacted with 290 grams of O2?
C4H10O+6O2-->4CO2+5H2O
First we find the limiting reagent.
C4H10O
Next we put the coefficient of the limiting reagent and the product into a ratio.
1:4
Next we divide this by the coefficient of the limiting reagent.
1/1=1 : 4/1=4
We then multiply the second number in the ratio by the number of moles in the limiting reagent.
4 x 0.867= 3.468
Finally, we multiply this result by the GFW of the product
3.468 x 44= 152.592 grams
That final number is your answer.
C4H10O+6O2-->4CO2+5H2O
First we find the limiting reagent.
C4H10O
Next we put the coefficient of the limiting reagent and the product into a ratio.
1:4
Next we divide this by the coefficient of the limiting reagent.
1/1=1 : 4/1=4
We then multiply the second number in the ratio by the number of moles in the limiting reagent.
4 x 0.867= 3.468
Finally, we multiply this result by the GFW of the product
3.468 x 44= 152.592 grams
That final number is your answer.