You were wrong.
Find the limiting reagent if 6.59 grams of C2H3OF were reacted with 3.40 grams of O2.
4C2H3OF+5O2=>8O+6H2O+2F2
First we find the GFW of each reactant.
GFW of C2H4: 62
GFW of O2: 32
Next we divide the number of grams of each reactant by the GFW.
6.59/62= 0.106
3.40/32= 0.106
Finally, we multiply each of the results by the coefficient of the other reactant/
0.106 x5= 0.53
0.106 x4= 0.424
Because 0.424 is smaller than 0.53, we know that the limiting reagent is O2.
4C2H3OF+5O2=>8O+6H2O+2F2
First we find the GFW of each reactant.
GFW of C2H4: 62
GFW of O2: 32
Next we divide the number of grams of each reactant by the GFW.
6.59/62= 0.106
3.40/32= 0.106
Finally, we multiply each of the results by the coefficient of the other reactant/
0.106 x5= 0.53
0.106 x4= 0.424
Because 0.424 is smaller than 0.53, we know that the limiting reagent is O2.